diff --git a/README.md b/README.md index 736822c..a97c985 100644 --- a/README.md +++ b/README.md @@ -131,10 +131,10 @@ So ALL my motors are 4-wire bipolar-series motors! Power_ supply_current = (5 * 1/3 * 2.0 Amps) + (1 * 1/3 * 1.0A) = 3.333 + 0.333 = 3.6667 or 4 Amps. - So for **my bipolar-series motors** I want to khow many Watts of power is 4 Amps at 48 VDC? + So for **my bipolar-series motors** I want to know many Watts of power is 4 Amps at 48 VDC? + + Answer: Watts = Volts * Amps - Answer: Watts = Volts * Amps - So, 48VDC * 4 Amp = 192 Watts or 200 Watts PSU (if the PSU supplies the full power without an aluminum plate for heat dissipation [PSU's Derating Curve]). Options for powering my Voron 2.4 printer at 48 VDC, and 24 VDC (running all HT motors from LDO at 48VDC) with the following: